Question

The maximum amount of $BaS{O}_4$ that can be obtained on mixing 0.5 mole $BaC{l}_2$ with 1 mole $H_{2}S{O}_4$ is:

• A. 0.5 mol
• B. 0.1 mol
• C. 0.15 mol
• D. 0.2 mol

Answer 1

The correct option is A 0.5 mol

$BaC{l}_2$ +$H_{2}S{O}_4$ $\to BaS{O}_4+2HCl$

1 mol of BaCl${}_2$ reacts with 1 mol $H_{2}S{O}_4$ to give 1 mol of $BaS{O}_4$.

Here , $BaC{l}_2$ is the limiting reagent.

Therefore, moles of $BaS{O}_4$ formed = moles of $BaC{l}_2$ present = $0.5mol$.