The mean and median of $100$ items are $50$ and $52$ respectively. The value of largest item is $100$ . If was later found that it it 110 and not 100 . The true mean and median are:

50.10, 51.5

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50.10, 52

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50, 51.5

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none of these

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Solution

The correct option is B $50.10, 52$
Mean of 100 items $= 50$

Sum of 100 items $= 50 \times 100 = 5000$

Correct Sum $= 5000 - 100 + 110$

$= 5010$

Correct mean $= \frac{5010}{100} = 50.10$

Median does not change when there is any change in the extreme numbers.

Hence Revised mean $= 50.10$ and median $= 52.$

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The mean and median of 100 items are 50 and 52 respectively. The value of largest item is 100 . If was later found that it it 110 and not 100 . The true mean and median are:

The correct option is B 50.10,52Mean of 100 items =50Sum of 100 items =50×100=5000 Correct Sum =5000−100+110=5010Correct mean =5010100=50.10Median does not change when there is any change in the extreme numbers.Hence Revised mean =50.10 and median =52.

The mean and median of $100$ items are $50$ and $52$ respectively. The value of largest item is $100$ . If was later found that it it 110 and not 100 . The true mean and median are: