1
Question
The mixture of colourless gases is:
The mixture of colourless gases is:
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Solution
The correct option is D CO2+CO+H2O
(2DU in A).
It may have either two (C=C) or one(C≡C) bond. Formation of three compounds on oxidation of (A) shows that it contains two (C=C)bonds.
(A) C8H14⟹CH3CHO(twoCatoms)(B)+(CH3CPCH2CH3)(two C atoms)(C)+HOOC−COOH(two C atoms)(D)(2DU in A).(B) reduces ammoniacal AgNO3 solution and gives iodoform test.
Therefore, (B) is an aldehyde and it is (CH3−CHO) (two-C-atom aldehyde).
(C) is a ketone containing ⎛⎜
⎜⎝CH3−O||C−⎞⎟
⎟⎠ group (since it gives iodoform test).
(D) is two-C dibasic acid since it gives CO2, CO, and H2O with conc. H2SO4,
(D) may be oxalic acid (HOOC - COOH) (two C atoms). Total C atoms in (C)must be four.
(2DU in A).
It may have either two (C=C) or one(C≡C) bond. Formation of three compounds on oxidation of (A) shows that it contains two (C=C)bonds.
(A) C8H14⟹CH3CHO(twoCatoms)(B)+(CH3CPCH2CH3)(two C atoms)(C)+HOOC−COOH(two C atoms)(D)
(2DU in A).
(B) reduces ammoniacal AgNO3 solution and gives iodoform test.
Therefore, (B) is an aldehyde and it is (CH3−CHO) (two-C-atom aldehyde).
(C) is a ketone containing ⎛⎜ ⎜⎝CH3−O||C−⎞⎟ ⎟⎠ group (since it gives iodoform test).
(D) is two-C dibasic acid since it gives CO2, CO, and H2O with conc. H2SO4,
(D) may be oxalic acid (HOOC - COOH) (two C atoms). Total C atoms in (C)must be four.
Therefore, (B) is an aldehyde and it is (CH3−CHO) (two-C-atom aldehyde).
(C) is a ketone containing ⎛⎜ ⎜⎝CH3−O||C−⎞⎟ ⎟⎠ group (since it gives iodoform test).
(D) is two-C dibasic acid since it gives CO2, CO, and H2O with conc. H2SO4,
(D) may be oxalic acid (HOOC - COOH) (two C atoms). Total C atoms in (C)must be four.
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