The molar conductivity of a 0-5 mol - dm 3 solution of AgN O 3 with electrolytic conductiviy of 5-76 - 10-3 S cm -1 at 298 K isA- 11-52 S cm 2 - molB- 2-88 cm 2 - molC- 0-086 S cm 2 - molD- 28-8 cm 2 - mol

The molar conductivity of a $0.5 m o l / d m^{3}$ solution of $A g N O_{3}$ with electrolytic conductiviy of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is

Q. The molar conductivity of a

0.5 m o l / d m^{3}

solution of

A g N O_{3}

with electrolytic conductivity of

5.76 \times 10^{- 3} S c m^{- 1}

at 298 K is

Q. Electrolytic conductivity of 0.02 mol/l solution of kcl at 298k is 2.48x10^-2 ohm^-1 cm^-1. Calculate it's molar conductivity.

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The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductiviy of 5.76×10−3 S cm−1 at 298 K is

The correct option is B 11.52 S cm2/mol Am=K×1000Molarity (M) =5.76×10−3 S cm−1×10000.5 mol cm−3=11.52 S cm2 mol−1

The molar conductivity of a $0.5 m o l / d m^{3}$ solution of $A g N O_{3}$ with electrolytic conductiviy of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is

The correct option is B
$11.52 S c m^{2} / m o l$

$A_{m} = \frac{K \times 1000}{M o l a r i t y (M)}$
$= \frac{5.76 \times 10^{- 3} S c m^{- 1} \times 1000}{0.5 m o l c m^{- 3}} = 11.52 S c m^{2} m o l^{- 1}$