Question

The molar ionic conductivities at infinite dilution of $A{g}^{+}$ is $61.92\times {10}^{-4}Smo{l}^{-1}{m}^{2}at{25}^{o}C$, the ionic mobility of $A{g}^{+}$ will be :

• A. $6.4\times {10}^{-8}$
• B. $6.192\times {10}^{-6}$
  
• C. $6.192\times {10}^{-4}$
• D. $3.2\times {10}^{-4}$

Answer 1

The correct option is A $6.4\times {10}^{-8}$

The relationship between ionic mobility and ionic conductance is $Ionicmobility=\frac{Ionicconductance}{96500}.$
Substitute values in the above equation.
$Ionicmobility=\frac{61.92\times {10}^{-4}{S}^{}{m}^2{mol}^{-1}}{96500}=6.4\times {10}^{-8}$.