The molarity of a solution having 8-4 volume strength of H 2 O 2 is-A- 0-75 MB- 1-5 MC- 0-50 MD- 2-5 M

The correct option is A 0.75 M 5.6 volume strength of H_2O_2 = 1 N 8.4 volume strength of H_2O_2= 8.4/5.6=1.5 N nbsp; Molarity = normality/n factor = 1. ...

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Standard XII

Chemistry

Hydrogen Peroxide

The molarity ...

Question

The molarity of a solution having 8.4 volume strength of $H_{2} O_{2}$ is:

$1.5 M$

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$0.75 M$

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$0.50 M$

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$2.5 M$

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Solution

The correct option is B

$0.75 M$

5.6 volume strength of $H_{2} O_{2}$ = $1 N$
8.4 volume strength of $H_{2} O_{2} = \frac{8.4}{5.6} = 1.5 N$
Molarity = $\frac{n o r m a l i t y}{n - f a c t o r} = \frac{1.5}{2} = 0.75 M$

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The molarity of a solution having 8.4 volume strength of H2O2 is:

The correct option is B 0.75 M 5.6 volume strength of H2O2 = 1 N 8.4 volume strength of H2O2=8.45.6=1.5 N Molarity = normalityn−factor=1.52=0.75 M

The molarity of a solution having 8.4 volume strength of $H_{2} O_{2}$ is:

The correct option is B

$0.75 M$

5.6 volume strength of $H_{2} O_{2}$ = $1 N$
8.4 volume strength of $H_{2} O_{2} = \frac{8.4}{5.6} = 1.5 N$
Molarity = $\frac{n o r m a l i t y}{n - f a c t o r} = \frac{1.5}{2} = 0.75 M$