The molarity of $H_{2} S O_{4}$ is $18$ M. Its density is $1.8 g m L^{- 1}$ . Hence, molality is

Open in App

Solution

Using formula,
$m o l a l i t y (m) = \frac{m o l a r i t y}{d e n s i t y - \frac{(m o l a r i t y \times m o l a r m a s s)}{1000}}$
Solving for m,
$m o l a l i t y (m) = \frac{18}{1.8 - \frac{(18 \times 98)}{1000}} = 500 m$

Suggest Corrections

Similar questions

Molarity of H2SO4 is 18 M. It's density is 1.8g/cm³, hence molality is?

H_{2} S O_{4}

H_{2} S O_{4}

H_{2} S O_{4}

H_{2} S O_{4}

18

8

c m^{- 3}

k g^{- 1}

(H_{2} O)

H_{2} S O_{4}

g / c m^{3}

Join BYJU'S Learning Program