The molecular formula of ethanoic acid $C_{2} H_{4} O_{2}$ . Its empirical formula is:

C_{4} H_{8}

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C H_{2} O

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C H O

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C H O_{2}

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Solution

The correct option is A $C H_{2} O$
The empirical formula of a compound is the simplest ratio of all the atoms present in that compound. The molecular formula of ethanoic acid is $C_{2} H_{4} O_{2}$ that is $2 : 4 : 2$ simplest ratio is $1 : 2 : 1$ hence the empirical formula is $C H_{2} O .$

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Similar questions

The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound ?

(a) $C_{9} H_{18} O_{9}$ (b) $C H_{2} O$ (c) $C_{6} H_{12} O_{6}$ (d) $C_{2} H_{4} O_{2}$

C H_{2} O

60

{C H}_{2} O

44

C H_{2} O

180

C H_{2} O

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