The monkey B shown in figure (5-E20) is holding on to the tail of the monkey A which is climbing up a rope. The masses of the monkeys A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail, what force should it apply on the rope in order to carry the monkey B with it? Take $g = 10 m / s^{2}$

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Solution

$30 - 20 = 2 \times a$
2a=10
$a = 5 m / s^{2}$

$T - 50 - 30 = 5 a$
$5 a = T - 80$
$T = 5 a + 80 = 5 \times 5 + 80$
$= 105 N$

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Q. The monkey B, shown in the figure (5−E20), is holding on to the tail of monkey A that is climbing up a rope. The masses of monkeys A and B are 5 kg and 2 kg, respectively. If A can tolerate a tension of 30 N in its tail, what force should it apply on the rope in order to carry monkey B with it? Take g = 10 m/s².

Figure

Q. The monkey

B

shown in figure is holding on to the tail of the monkey

A

which is climbing up a rope. The masses of the monkeys

A

and

B

are

5 k g

and

2 k g

respectively. If

A

can tolerate a tension of

30 N

in its tail, what force maximum should it apply on the rope in order to carry the monkey

B

with it? Take

g = 10 m / s^{- 2}

The monkey B shown in figure is holding on to the tail of the monkey A which is climbing up a rope. The masses of the monkeys A and B are 5 kg and 2 kg respectively. If A can tolerate a tension of 30 N in its tail, what force should it apply on the rope in order to carry the monkey B with it ? Take g = 10 $m / s^{2}$ .