Question

The normality of $10$% (mass/volume) acetic acid is :

• A. $1N$
• B. $10N$
• C. $1.7N$
• D. $0.83N$

Answer 1

Answer: (C)

$1.7N$

Normality of a solution is defined as the number of equivalents of solute present in one litre (1000 mL) solution.
$N=\frac{\text{Equivalent of acid}\times 1000}{\text{Volume of solution}}=\frac{10\times 1000}{60\times 100}=1.66=1.7$ (approx)