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Question

The normality of 10% (w/v) acetic acid is:

A
N
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B
10 N
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C
1.67 N
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D
0.83 N
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Solution

The correct option is C 1.67 N
10% w/v means 10 g of acetic acid is present in 100 mL of solution.
Moles of acetic acid = given massmolar mass=1060=0.167

Molarity=moles of solutetotal volume of solution (mL)×1000=0.167100×1000=1.67 M
Since the n-factor for acetic acid is 1, normality = 1.67 N

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