Question

The number of all possible matrices of order $3\times 3$ with each entry $0$ or $1$ is:

• A. $27$
• B. $18$
• C. $81$
• D. $512$

Answer 1

The correct option is D $512$

The given matrix of the order $3\times 3$ has $9$ elements and each of these elements can be either $0$ or $1$.
Now, each of the $9$ elements can be filled in two possible ways.
Therefore, by the multiplication principle, the required number of possible matrices is $2^9=512$