Question

The number of atoms in $0.1\text{mol}$ of a triatomic gas is $(N_A=6.02\times {10}^{23}{\text{mol}}^{-1})$

• A. $1.806\times {10}^{23}$
• B. $6.026\times {10}^{22}$
• C. $1.800\times {10}^{22}$
• D. $3.600\times {10}^{23}$

Answer 1

The correct option is A $1.806\times {10}^{23}$

Let the triatomic gas be $X_3$
Number of atoms in $1$ mol of $X_3=N_A\times \times 3$
So number of atoms in $0.1$ mol of $X_3=6.023\times {10}^{23}\times 0.1\times 3$
$=1.806\times {10}^{23}$

Hence the correct answer is option (c).