Question

The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C 3

No.of links : $l=8$
No.of revolute joints,
$j=9$
No.of higher pair,
$h=0$
$\therefore$ Number of degrees of freedom,
$n=3(l-1)-2j-h$
$=3(8-1)-2\times 9-0$
$=3$