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Head Elements (Group 1)

The number of...

Question

The number of electrons involved in the reduction of nitrate ion to hydrazine is:

A

8

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B

5

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C

3

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D

7

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Solution

The correct option is D
7

$N O_{3}^{-} \to N_{2} H_{4}$

Oxidation state of $N$ in $N O_{3}^{-}$ is +5. Oxidation state of $N$ in $N_{2} H_{4}$ is -2.

So, the number of electrons involved are 7.

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