The number of geometrical isomers of $C H_{3} - C H = C H - C H = C H - C H = C H C l$ are:

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Solution

The correct option is D 8
The given compound is a unsymmetrical compound. It has different terminal groups ( methyl and chlorine).
The formula used to determinne the number of geometrical isomers in compound having different terminal groups is, $2^{n}$ , where n is the number of dounle bond present in the molecule.
In the given compound we have 3 double bond so n = 3
Therefore,
No. of geometrical isomers = $2^{n}$
= $2^{3}$
= 8.

Hence, unsymmetrical compound with 3 double bonds has 8 stereoisomers.

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