The number of geometrical isomers possible for the compound are:

$C H_{3} - C H = C H - C H = C H - C_{2} H_{5}$

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Solution

The correct option is A 4
In $C H_{3} - C H = C H - C H = C H - C_{2} H_{5}$ , the number of double bonds is equal to 2.

Therefore, the number of geometrical isomers $= 2^{2}$ $= 4$ .

So, the correct option is $C$

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Similar questions

C H_{3} - C H = C H - C H = C H - C H_{3}

C H_{3} - C H = C H - C H = C H - C_{2} H_{5}

C H_{3} - C H = C H - C H = C H - C H = C H C l

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