The number of molecules in 4.25 g of ammonia is approximately

0.5 X 10²³

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1.5 X 10²³

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3.5 X 10²³

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2.5 X 10²³

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Solution

The correct option is B
1.5 X 10²³

Calculate using mole concept

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Similar questions

4.25 g

N H_{3}

4.25

N H_{3}

4.25 g

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0 \times 10^{23}$ (b) $1.5 \times 10^{23}$
(c) $2.0 \times 10^{23}$ (d) $3.5 \times 10^{23}$

4.25 g

N H_{3}

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