The correct option is A 0.1 moles
AgNO3 + NaCl →AgCl + NaNO3
Molar Mass of AgCl = 143.32 g
Number of moles of AgCl in 14.34 g of AgCl=Given mass of AgClMolar Mass of AgCl=14.343143.43=0.1 mol
From the balanced chemical reaction, 1 mole of NaCl produces 1 mole of AgCl
So, the number of moles of NaCl that produces 0.1 mol of AgCl=0.1 mol