Question

The number of moles of potassium salt, i.e., $KH{C}_2{O}_4\cdot H2C_2{O}_4\cdot 2H_{2}O$ oxidized by one mole of permanganate ion is :

• A. $\frac{2}{5}$
• B. $\frac{4}{5}$
• C. $1$
• D. $\frac{5}{4}$

Answer 1

The correct option is D $\frac{5}{4}$

The reaction is as follows:
$KH{C}_2{O}_4.H_2{C}_2{O}_4+KMn{O}_4\to M{n}^{+2}+C{O}_2$
+3 +3 +7 +2 +4
So, one mole of $KMn{O}_4$ oxidises $\frac{5}{4}$ moles of potassium salt.