Question

The number of unpaired electrons in $F{e}^{2+}$ are :

• A. 4
• B. 5
• C. 3
• D. 6

Answer 1

The correct option is A 4

$Fe(Z=26):\left[Ar\right]3d^{6}4s^2$

$F{e}^{2+}:\left[Ar\right]3d^6$

Therefore, there are 4 unpaired electrons in $F{e}^{2+}$ and so option (a) is the correct answer