The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip took 8 h, calculate the average speed of the car in $k m h^{- 1}$ and $m s^{- 1}$

50 km/h or 13.9 m/s

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40 km/h or 12.5 m/s

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50 km/h or 12.5 m/s

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40 km/h or 13.9 m/s

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Solution

The correct option is A 50 km/h or 13.9 m/s
Answer is A.

It is given that the total distance travelled by the car is 2400 km-2000 km = 400 km, that is, 400000 m and the total time taken =8 hours, that is, $8 \times 60 \times 60 = 28800 s e c o n d s .$ .
Average speed in km/hr = total distance/total time = 400/8 = 50 km/hr.
Average speed in m/s = total distance/total time = 400000/28800 = 13.89 m/s.

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The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip took 8 h, calculate the average speed of the car in kmh−1 and ms−1

The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip took 8 h, calculate the average speed of the car in $k m h^{- 1}$ and $m s^{- 1}$