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Reduction of Alkyl Halide

The organic p...

Question

The organic product formed in the reaction.
$C_{6} H_{5} C O O H I . L i A l H_{4} - ----- \to$

C_{6} H_{5} C H_{2} O H

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C_{6} H_{5} C O O H

C H_{4}

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C_{6} H_{5} C H_{3}

C H_{3} O H

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C_{6} H_{5} C H_{3}

C H_{4}

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Solution

The correct option is A $C_{6} H_{5} C H_{2} O H$
Lithium aluminium hydride $(L i A l H_{4})$ is an stronger reducing agent that can reduce aldehydes, ketones, carboxylic acids and esters.
$L i A l H_{4}$ reduces $- C O O H$ group to $- C H_{2} O H$ group. $C_{6} H_{5} C O O H L i A l H_{4} - --- \to C_{6} H_{5} C H_{2} O H$
Hence option (a) is correct.

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The major organic product formed in the following reaction is:

C H_{2} = C H (C H_{2})_{8} C O O H + H B r P e r o x i d e - ---- \to

C H_{2} = C H (C H_{2})_{8} C O O H + H B r p e r o x i d e \to

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