Question

The oxidation number of nickel in $K_4\left[Ni\right(CN{)}_4]$ is

• A. -2
• B. -1
• C. 2

Answer 1

$K_4\left[\stackrel{\ast }{Ni}\right(CN{)}_4]$
$4\times (+1)+x+4\times (-1)=0$
$+4+x-4=0\Rightarrow x=0$