Question

The oxidation number of sulfur in $H_{2}S{O}_4$ is :

• A. $+2$
• B. $+3$
• C. $+4$
• D. $+6$
• E. $+8$

Answer 1

The correct option is D $+6$

Let X be the oxidation number of S in $H_{2}S{O}_4$.
The oxidation number of hydrogen is +1 and the oxidation number of oxygen is -2.
$2(+1)+X+4(-2)=02+X-8=0X-6=0X=+6$
Hence, the oxidation number of S in $H_{2}S{O}_4$is +6.