The oxidation number of sulphur in sodium thiosulphate is:

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Solution

The correct option is C 2
$x$
$N a_{2} S_{2} O_{3}$
$+ 2 + 2 x - 6 = 0$
$2 x = 4$
$x = + 2$ Thus oxidation state of 'S' in sodium thiosulphate is +2

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The average oxidation state of Sulphur in Sodium Thiosulphate is +_____.

The average oxidation state of Sulphur in Sodium Thiosulphate is +___.

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N a_{2} S_{2} O_{3}

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