The oxidation state and valency of $A l$ in $[A l C l (H_{2} O)_{5}]^{2 +}$ :

+ 6

+ 3

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+ 3

+ 6

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+ 6, + 6

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+ 3

+ 3

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Solution

The correct option is A $+ 3$ & $+ 6$
Chloride gets $- 1$ and water molecule oxidation state is $0$ hence overall oxidation state becomes $x + 0 - 1 = 2$ from which we get $x = 3$ and total number of ligands surrounding aluminium is $6$ nothing but valency.

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An element X forms an oxide $X O_{3}$ , the valency of element X is:

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The oxidation state and valency of Al in [AlCl(H2O)5]2+:

The correct option is A +3 & +6Chloride gets −1 and water molecule oxidation state is 0 hence overall oxidation state becomes x+0−1=2 from which we get x=3 and total number of ligands surrounding aluminium is 6 nothing but valency.

The oxidation state and valency of $A l$ in $[A l C l (H_{2} O)_{5}]^{2 +}$ :

The correct option is A $+ 3$ & $+ 6$
Chloride gets $- 1$ and water molecule oxidation state is $0$ hence overall oxidation state becomes $x + 0 - 1 = 2$ from which we get $x = 3$ and total number of ligands surrounding aluminium is $6$ nothing but valency.