Question

The oxidation state of iodine in $H_{4}I{O}_6^{\ominus }$ is :

• A. $+7$
• B. $-1$
• C. $+5$
• D. $+1$

Answer 1

The correct option is A $+7$

Let $x$ be the oxidation state of $I$ in $H_{4}I{O}_6^{\ominus }$.
Since, the overall charge on the complex is $-1$, the sum of oxidation states of all elements in it should be equal to $-1$.
Therefore,
$+4+x+6(-2)=-1$
or, $x=+7$
Hence, the oxidation state of $I$ is $+7$.