Question

The oxidation state of oxygen in $K{O}_3$, $N{a}_2{O}_2$ are respectively :

• A. 3,2
• B. 1,0
• C. 0,1
• D. -0.33,-1

Answer 1

The correct option is D

-0.33,-1

We know that the sum of oxidation number of all the elements in a compound is equal to zero.
Using this information we can find the oxidation number of oxygen in both the compounds.
Let the oxidation number of oxygen in $K{O}_3$ be $x$
So we can formulate the equation
$K{O}_3$$⟹$ $+1+3\times x=0$

Hence, $x=\frac{-1}{3}$
Let the oxidation number of oxygen in $N{a}_2{O}_2$ be $y$
So we can formulate the equation

$N{a}_2{O}_2$$⟹$ $+2+2\times y=0$
Hence, $y=-1$

So the correct option is -0.33, -1