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Question

The oxidation state of sulphur in the anions SO2−3,S2O2−4 and S2O2−6 follows the order :

A
S2O26<S2O24<SO23
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B
SO23<S2O24<S2O26
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C
S2O24<SO23<S2O26
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D
S2O24<S2O26<SO23
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Solution

The correct option is C S2O24<SO23<S2O26
O.S. of S in SO23,
x6=2
x=+4

O.S. of S in S2O24,
2x8=2
x=3


O.S. of S in S2O26,
2x12=2
x=+5

The correct order of increasing O.S. is;

S2O24<SO23<S2O26

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