You visited us 1 times! Enjoying our articles? Unlock Full Access!

Electronic Configuration and Oxidation States

The oxidation...

Question

The oxidation states of nitrogen in $N H_{4} N O_{3}$ are :

-3 , + 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-4, + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 3, + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+3 , -5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A -3 , + 5
$N H_{4} N O_{3} (- 3 N H_{4}^{+}, + 5 N O_{3} -)$
So, the oxidation states of nitrogen are -3 and +5.

Suggest Corrections

Similar questions

H N O_{3}

- 3, + 5

N H_{4} N O_{3}

\frac{- 1}{3}

N_{3} H

+ 5

H_{3} P O_{3}

+ 3

\frac{+ 1}{3}

N H_{4} N O_{3}

Oxidation states of $P$ in $H_{4} P_{2} O_{6}, H_{4} P_{2} O_{6}, H_{4} P_{2} O_{7}$ are respectively:

H I O_{4}, H_{3} I O_{5}

H_{5} I O_{6}

P O C l_{3}, H_{2} P O_{3} a n d H_{4} P_{2} O_{6}

Join BYJU'S Learning Program