The parallel sides of a trapezium are 12 cm and 9 cm and the distance between them is 8 cm. Find the area of the trapezium.

Open in App

Solution

$Area of the trapezium = \frac{1}{2} \times (sum of the parallel sides) \times distance between the parallel sides = \frac{1}{2} \times (12 + 9) \times 8 = 21 \times 4 = 84 {cm}^{2}$

So, the area of the trapezium is 84 cm².

Suggest Corrections

Similar questions

The parallel sides of a trapezium are 12 cm and 9 cm and the diatance between them is 8 cm. Find the area of the trapezium.

Q. Find area of trapezium whose parallel sides

9 c m

and

5 c m

respectively and the distance between these sides is

8 c m

Q. If the lengths of parallel sides of trapezium are

8 c m, 9 c m

and the distance between the parallel sides is

6 c m

, then its area is

Q. The two parallel sides of a trapezium and the distance between them are in the ratio 5 : 7 : 4. If the area of the trapezium is 216

c m^{2}

, find its height.

Fill in the blanks.
(i) Area of triangle = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(ii) Area of a ||gm = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(iii) Area of a trapezium = $\frac{1}{2} \times (. . . . . . . . .) \times (. . . . . . . . .)$ .
(iv) The parallel sides of a trapezium are 14 cm and 18 cm and the distance between them is 8 cm. The area of the trapezium is ......... cm².

Join BYJU'S Learning Program

The parallel sides of a trapezium are 12 cm and 9 cm and the distance between them is 8 cm. Find the area of the trapezium.

Area of the trapezium=12×sum of the parallel sides×distance between the parallel sides=12×12+9×8=21×4=84 cm2 So, the area of the trapezium is 84 cm2.

$Area of the trapezium = \frac{1}{2} \times (sum of the parallel sides) \times distance between the parallel sides = \frac{1}{2} \times (12 + 9) \times 8 = 21 \times 4 = 84 {cm}^{2}$

So, the area of the trapezium is 84 cm².