Question

The parameter type and the matrix representation of the relevant two-port parameters that describe the circuit shown are

• A. z-parameters, $\left[\begin{array}{cc}0& 0\\ 0& 0\end{array}\right]$
• B. h-parameters, $\left[\begin{array}{cc}1& 0\\ 0& 1\end{array}\right]$
• C. g-parameters, $\left[\begin{array}{cc}0& 0\\ 0& 0\end{array}\right]$
• D. z-parameters, $\left[\begin{array}{cc}1& 0\\ 0& 1\end{array}\right]$

Answer 1

The correct option is C g-parameters, $\left[\begin{array}{cc}0& 0\\ 0& 0\end{array}\right]$

$I_1=g_{11}{V}_1+g_{12}{I}_2$
$V_2=g_{21}{V}_1+g_{22}{I}_2$

Since port-1 is open circuit, $I_{!}=0$
Port-2 is short-circuit, $V_2=0$
$g_{11}={\begin{array}{c}\frac{I_1}{V_1}\end{array}|}_{I_2=0}=\frac{0}{V_1}=0$
$g_{12}={\begin{array}{c}\frac{I_1}{I_2}\end{array}|}_{V_1=0}=\frac{0}{I_2}=0$
$g_{21}={\begin{array}{c}\frac{V_2}{V_1}\end{array}|}_{I_2=0}=\frac{0}{V_1}=0$
$g_{22}={\begin{array}{c}\frac{V_2}{I_1}\end{array}|}_{V_1=0}=\frac{0}{I_2}=0$
So, g-parameters,
$=\left[\begin{array}{cc}{g}_{11}& g_{12}\\ g_{21}& g_{22}\end{array}\right]=\left[\begin{array}{cc}0& 0\\ 0& 0\end{array}\right]$