The peak value of an alternating e-m-f- E is given by E - E 0cos- t is 10 volts and its frequency is 50 Hz- At time t -1-600 sec- the instantaneous e-m-f-isA- 10 VB- 5 -3 VC- 5 VD- 1 V

The peak value of an alternating e.m.f. E given by $E = E_{0} cos ω t$ is 10 volt and frequency is 50 Hz. At time $t = (1 / 600)$ sec, the instantaneous value of e.m.f. is

Q. The peak value of an alternating emf

E

given by

E = E_{0} c o s ω t

10 V

and frequency is

50 H z

. At time

t = (\frac{1}{600}) s

, the instataneous value of e.m.f. is:

Q. The peak value of an alternating emf is given by

E = E_{0} c o s (w t)

is 10 volt and its frequency is 50 Hz. At a time

t = (\frac{1}{600})

second, the instantaneous value of the emf is:

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The peak value of an alternating e.m.f. E is given by E=E0cos ωt is 10 volts and its frequency is 50 Hz. At time t=1600sec, the instantaneous e.m.f. is

The correct option is B 5√3VE=E0cos ωt=E0 cos2πtT=10 cos2π×50×1600=10 cosπ6π6=5√3volt.

The peak value of an alternating e.m.f. E is given by $E = E_{0} c o s ω t$ is 10 volts and its frequency is 50 Hz. At time $t = \frac{1}{600} s e c,$ the instantaneous e.m.f. is

The correct option is B $5 \sqrt{3} V$
$E = E_{0} c o s ω t = E_{0} c o s \frac{2 π t}{T} = 10 c o s \frac{2 π \times 50 \times 1}{600} = 10 c o s \frac{π}{6} \frac{π}{6} = 5 \sqrt{3} v o l t .$