Question

The percent ionic character in $HCl$ is 18.08. The observed dipole moment is 1.08 D. Find the internuclear distance in $HCl$.

Answer 1

% ionic character in $HCl=18.08$

Dipole moment $=1.08D$

$=\frac{1.08}{2.9979\times {10}^{29}}$

$=0.3602\times {10}^{-29}cm$

$\mu =0.0199\times {10}^{-27}cm$

$d=\frac{\mu }{e}$

$d=0.0124\times {10}^{-10}m$