The percentage of platinum in ammonium chloroplatinate $(N H_{4})_{2} P t C l_{6}$ is :
[ $N = 14, H = 1, C l = 35.5, P t = 195$ ]

22 %

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53. 34 %

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32.93 %

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44 %

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Solution

The correct option is C $44 %$
$(N H_{4})_{2} P t C l_{6}$ , molar mass $= 444$ gm and it contains 195 gm $P t$ , so % of $P t$ $= 195 \times \frac{100}{444} \approx 44$ .

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The percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6 is :[N=14,H=1,Cl=35.5,Pt=195]

The correct option is C 44%(NH4)2PtCl6, molar mass =444 gm and it contains 195 gm Pt, so % of Pt=195×100444≈44.

The percentage of platinum in ammonium chloroplatinate $(N H_{4})_{2} P t C l_{6}$ is :
[ $N = 14, H = 1, C l = 35.5, P t = 195$ ]

The correct option is C $44 %$
$(N H_{4})_{2} P t C l_{6}$ , molar mass $= 444$ gm and it contains 195 gm $P t$ , so % of $P t$ $= 195 \times \frac{100}{444} \approx 44$ .