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Question

Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6.

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Solution

Atomic weight of platinum is 195 g.
Molecular mass of (NH4)2PtCl6 = [2(14 + 4) + 195 + 6(35.5)] g = 444 g
Percentage of platinum=Mass of platinum in the compoundMolecular mass of the compound×100Percentage of platinum=195444×100=43.9944%


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