Question

# Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6.

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Solution

## Atomic weight of platinum is 195 g. Molecular mass of (NH4)2PtCl6 = [2(14 + 4) + 195 + 6(35.5)] g = 444 g $\mathrm{Percentage}\mathrm{of}\mathrm{platinum}=\frac{\mathrm{Mass}\mathrm{of}\mathrm{platinum}\mathrm{in}\mathrm{the}\mathrm{compound}}{\mathrm{Molecular}\mathrm{mass}\mathrm{of}\mathrm{the}\mathrm{compound}}×100\phantom{\rule{0ex}{0ex}}\mathrm{Percentage}\mathrm{of}\mathrm{platinum}=\frac{195}{444}×100=43.99\approx 44%$

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