Question

The perimeter of a rectangle is $12m$. The length is $3$ more than twice its width. What is the area of the rectangle?

• A. $5$
• B. $6$
• C. $9$
• D. $4$

Answer 1

The correct option is A $5$

Let length and width be $l$ and $b$.

The perimeter of the rectangle is given by
$2(l+b)=12$
$\Rightarrow l+b=6$

According to the given condition
$l=3+2b$
$\Rightarrow 6-b=3+2b$
$\Rightarrow 3b=3$
$b=1$

Using this value of $b$,

$l+1=6$

$\Rightarrow l=5$

$\therefore$ the area of the rectangle $=l\times b=5\times 1=5$