The perimeter of a rectangular field is $\frac{3}{5}$ km. If the length of the field twice its width. Find the area of the rectangle in sq. meters.

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Solution

given $l = 2 b$ fpr the given triangle
Perimeter $= 2 (l + b) =$ $2 (3 b) = \frac{3}{5} k m s$
$b = 0.1 k m s, l = 0.2 k m s$
Area $= l b = 0.1 \times 0.2 = 0.02 k m^{2}$

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The perimeter of a rectangular field is 35km. If the length of the field twice its width. Find the area of the rectangle in sq. meters.

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The perimeter of a rectangular field is $\frac{3}{5}$ km. If the length of the field twice its width. Find the area of the rectangle in sq. meters.

given $l = 2 b$ fpr the given triangle
Perimeter $= 2 (l + b) =$ $2 (3 b) = \frac{3}{5} k m s$
$b = 0.1 k m s, l = 0.2 k m s$
Area $= l b = 0.1 \times 0.2 = 0.02 k m^{2}$