Question

the perimeter of the rectangle is 72 m. its length is 10 m more than its breadth. find the dimensions of the rectangle

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{breadth}\mathrm{of}\mathrm{the}\mathrm{rectangle}=\mathrm{x}\mathrm{m} \\ \mathrm{Then}\mathrm{the}\mathrm{length}\mathrm{of}\mathrm{the}\mathrm{rectangle}=\left(\mathrm{x}+10\right)\mathrm{m} \\ \mathrm{Perimeter}=72\mathrm{m} \\ \Rightarrow 2\left(\mathrm{length}+\mathrm{breadth}\right)=72 \\ \Rightarrow \mathrm{length}+\mathrm{breadth}=36 \\ \Rightarrow \mathrm{x}+10+\mathrm{x}=36 \\ \Rightarrow 2\mathrm{x}+10=36 \\ \Rightarrow 2\mathrm{x}=36-10 \\ \Rightarrow 2\mathrm{x}=26 \\ \Rightarrow \mathrm{x}=13 \\ \mathrm{So},\mathrm{length}\mathrm{of}\mathrm{rectangle}=13+10=23\mathrm{m} \\ \mathrm{breadth}\mathrm{of}\mathrm{rectangle}=13\mathrm{m} \end{gathered}$$