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Question

The period of a simple pendulum measured by inside a stationary lift 'T' . If the lift starts moving upward with a acceleration g/3 . What will be the time period?

A
T/3
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B
3T
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C
32T
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D
32T
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Solution

The correct option is C 32T

Time period of pendulum, TP=2πstringlengthdownwardacceleration=2πLay

At stationary lift, acceleration is ay=g

Time period is T=2πLg....(1)

Lift accelerate upward, a=g+g3=4g3

Time period is T=2πL4g/3=32T

Hence, time period will be 32T


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