The period of a simple pendulum measured by inside a stationary lift 'T' . If the lift starts moving upward with a acceleration g/3 . What will be the time period?
Time period of pendulum, TP=2π√stringlengthdownwardacceleration=2π√Lay
At stationary lift, acceleration is ay=g
Time period is T=2π√Lg....(1)
Lift accelerate upward, a=g+g3=4g3
Time period is T′=2π√L4g/3=√32T
Hence, time period will be √32T