wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

The period of a simple pendulum measured by inside a stationary lift 'T' . If the lift starts moving upward with a acceleration g/3 . What will be the time period?

A
T/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32T
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
32T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 32T

Time period of pendulum, TP=2πstringlengthdownwardacceleration=2πLay

At stationary lift, acceleration is ay=g

Time period is T=2πLg....(1)

Lift accelerate upward, a=g+g3=4g3

Time period is T=2πL4g/3=32T

Hence, time period will be 32T


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Pendulum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon