Question

The period of oscillation of a particle in SHM is $\pi$ sec and its amplitude of vibration is 10 cm.The acceleration of the particle $\pi$ /12 s after passing the mean position is:

• A. $20\sqrt{3}cm/s^2$
• B. $20cm/s^2$
• C. $20/\sqrt{3}cm/s^2$
• D. $2\sqrt{3}cm/s^2$

Answer 1

Answer: (B)

$20cm/s^2$

$a=-{\omega }^{2}x$
$\omega =\frac{2\pi }{T}=\frac{2\pi }{\pi }=2rad/s$
$x=Asin\left(\omega t\right)$
$=Asin\left(2t\right)=10sin\left(\frac{\pi }{6}\right)$
$=5cm$
$a=-4\times 5$
$=-20cm/s^2$