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Question

The point charges q1=2μC and q2=1μC are placed at distances b= 1 cm and a = 2 cm from the origin on the y and x axes as shown in Fig. 11.50. The electric field vector at point P (a, b) will subtend an angle θ with the x-axis given by

A
tanθ=1
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B
tanθ=2
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C
tanθ=3
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D
tanθ=4
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Solution

The correct option is C tanθ=3
The point charge q1=2μC
q2=1μC
b=1cm
a=2cm
P(a,b)
θ= angle with the xaxis given by
tanθ=q1+q2=2+1=3

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