The potentiometer wire of length 100cm and resistance 9- is joined to a cell of e-m-f 10V and internal resistance 1- Another cell of e-m-f 5V and internal resistance 2- is connected and shown in Fig- The galvanometer G shows no deflection when the length AC is

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Magnetic Field Due to a Circular Arc at the Centre

The potentiom...

Question

The potentiometer wire of length $100 c m$ and resistance $9 Ω$ is joined to a cell of e.m.f $10 V$ and internal resistance $1 Ω$ . Another cell of e.m.f $5 V$ and internal resistance $2 Ω$ is connected and shown in Fig. The galvanometer $G$ shows no deflection when the length AC is

52.52 c m

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53.56 c m

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54.2 c m

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55.55 c m

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Solution

The correct option is D $55.55 c m$
First of all we should find potential gradient
Current in potentiometer $= \frac{10}{9 + 1} = 1 A$
Potential difference across potentiometer $= i R = 1 \times 9 = 9 V$
potential $C_{1}$ radient $= k = \frac{V}{L} = \frac{9}{100} \times 100 9 \frac{V}{m}$
$E M F m = K l (l = b a l a n c i n g l e n g t h)$
$5 = K l$
$l = \frac{5}{9} m \frac{5}{9} \times 100 l = \frac{500}{9}$
$A C = 55.55 c m$

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The potentiometer wire of length 100cm and resistance 9Ω is joined to a cell of e.m.f 10V and internal resistance 1Ω. Another cell of e.m.f 5V and internal resistance 2Ω is connected and shown in Fig. The galvanometer G shows no deflection when the length AC is

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The potentiometer wire of length $100 c m$ and resistance $9 Ω$ is joined to a cell of e.m.f $10 V$ and internal resistance $1 Ω$ . Another cell of e.m.f $5 V$ and internal resistance $2 Ω$ is connected and shown in Fig. The galvanometer $G$ shows no deflection when the length AC is