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Gay Lussac's Law, Avagadro's Law

The pressure ...

Question

The pressure of 11 gm of a gas which is placed in a 4 litres container at $127^{o} C$ is 2 atm, then the gas would be? (Take $R = 0.08 l t r . a t m / m o l K)$

N_{2} O

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O_{3}

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N O_{2}

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C O_{2}

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Solution

The correct options are
A $N_{2} O$
D $C O_{2}$
$P V = \frac{W}{M} R T$
$M = \frac{W R T}{P V} = \frac{11 \times 0.08 \times 400}{2 \times 4} = 44$
gases are $N_{2} O$ & $C O_{2}$ .

Suggest Corrections

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