Question

The primary coil of an idea step up transformer has $100turns$ and transformation ratio is also $100$. The input voltage and power are respectively $220V$ and $1100W$ calculate $\left(2M\right)$

1. Number of turns in secondary

2. Current in primary

3. Voltage across secondary

4. Current in secondary

5. Power in secondary

Answer 1

Given that,

Input voltage $V_{input}=220V$

Power $P_{input}=1100W$

Number of turns $N_P=100$

$r=100$

(I). Number of turns in secondary

We know that,

$r=\frac{N_s}{N_p}$

$N_{{}_S}=r\times N_p$

$N_s=100\times 100$

$N_s=10000$

(II).The current in primary

We know that

$I_p=\frac{P_{input}}{V_p}$

$I_P=\frac{1100}{220}$

$I_p=5A$

(III). The Voltage across secondary

We know that

$r=\frac{V_s}{V_p}$

$V_s=r\times V_p$

$V_s=100\times 220$

$V_s=22000V$

(IV). The Current in secondary

We know that,

$r=\frac{I_p}{I_S}$

$I_s=\frac{I_p}{r}$

$I_s=\frac{5}{100}$

$I_s=0.05A$

(V). The power in secondary

We know that,

For ideal transformer

Power in secondary = power in primary

$P_s=1100W$

This is the solution