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Question

# The probability that a leap year selected at random contains $53$ Sundays is

A

$\frac{7}{366}$

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B

$\frac{28}{183}$

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C

$\frac{1}{7}$

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D

$\frac{2}{7}$

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Solution

## The correct option is D $\frac{2}{7}$Explanation for the correct optionWe know that a leap year has $366$days.We have $52$ weeks and $2$ days. So, a leap year has $52$Sundays.The remaining $2$days can be,(Sunday, Monday),(Monday, Tuesday),(Tuesday, Wednesday),(Wednesday, Thursday),(Thursday, Friday),(Friday, Saturday),(Saturday, Sunday)We have $7$possibilities, from these possibilities we have two Sundays in it.So, the required probability is $\frac{2}{7}$Hence, option(D) is the correct answer i.e. $\frac{2}{7}$

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