The product a-ba-ba2-a b-b2a2-a b-b2 is equal toa a6-b6b a6-b6c a3-b3d a3-b3

We have to find the product of Using identity nbsp; We can rearrange as nbsp; Again using the identity Here Hence the product of is The c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

(x±a)(x±b) = x²±(a+b)x+ab.

The product a...

Question

The product (a + b) (a − b) (a² − ab + b²) (a² + ab + b²) is equal to

(a) a⁶ + b⁶

(b) a⁶ − b⁶

(c) a³ − b³

(d) a³+ b³

Open in App

Solution

Suggest Corrections

Similar questions

On Resolving $a^{6} - b^{6}$ into factors give $(a + b) (a - b) (a^{2} - a b + b^{2}) (a^{2} + a b + b^{2})$ .

$The product (a + b) (a - b) (a^{2} - a b + b^{2}) (a^{2} + a b + b^{2})$ is equal to

(a^{2} - b^{2}) (a^{2} + a b + b^{2}) - a^{3} + b^{3}

a^{6} - b^{6}

a^{3} - b^{3} = (a - b) (a^{2} + b^{2} + a b)

Join BYJU'S Learning Program