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Multiplication of Any Polynomial

The product o...

Question

The product of $(3 x^{2} - 5 x + 6)$ and $- 8 x^{3}$ when $x = 0$ is

\frac{1}{2}

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Solution

The correct option is D $0$
$(3 x^{2} - 5 x + 6) \times - 8 x^{3}$
= $- 24 x^{5} + 40 x^{4} - 48 x^{3}$
Put $x = 0,$ we get value as $0$

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:

x^{2} + 5 x + 6 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 5 x - 6 = 0

x^{2} - 5 x - 6 = 0

\frac{1 + x^{2}}{x^{2} - 5 x + 6} < 0

Find the value of x if ${| x + 1 |}^{2}$ - 5| $| x + 1 |$ + 6 = 0

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