Question

The radius of a capillary tube is reduced to half of its original volume. how does it affect the rise of liquid in the capillary tube?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{If}\mathrm{the}\mathrm{radius}\mathrm{of}\mathrm{capillary}\mathrm{is}\mathrm{reduced}\mathrm{to}\mathrm{half},\mathrm{the}\mathrm{rise}\mathrm{of}\mathrm{liquid}\mathrm{column}\mathrm{will}\mathrm{be}\mathrm{two}\mathrm{times} \\ \mathrm{as}\mathrm{h}\mathrm{\alpha }\frac{1}{\mathrm{r}} \\ \mathrm{where},\mathrm{h}=\mathrm{rise}\mathrm{of}\mathrm{liquid}\mathrm{column} \\ \mathrm{r}=\mathrm{radius}\mathrm{of}\mathrm{capillary} \end{gathered}$$